2 回复
import { common } from '@kit.AbilityKit';
import { BusinessError } from '@kit.BasicServicesKit';
@Entry
@Component
struct Index {
@State message: string = 'Hello World';
context = getContext(this) as common.UIAbilityContext
build() {
Button("appCrash").onClick(()=>{
try {
this.context.terminateSelf((err: BusinessError) => {
if (err.code) {
// 处理业务逻辑错误
console.error(`terminateSelf failed, code is ${err.code}, message is ${err.message}`);
return;
}
// 执行正常业务
console.info('terminateSelf succeed');
});
} catch (err) {
// 捕获同步的参数错误
let code = (err as BusinessError).code;
let message = (err as BusinessError).message;
console.error(`terminateSelf failed, code is ${code}, message is ${message}`);
}
})
}
}
关于HarmonyOS 鸿蒙Next退出应用程序的代码，以下是一个示例：
在鸿蒙Next系统中，你可以通过重写onBackPress事件来实现退出应用程序的功能。以下是一个简单的代码示例：
import common from "@ohos.app.ability.common";
import { promptAction } from "@kit.ArkUI";
@Entry
@Component
struct IndexComponent {
private lastBackPressTime: number = 0;
private exitTimeInterval: number = 2000;
onBackPress(): boolean {
const currentTime = Date.now();
if (currentTime - this.lastBackPressTime < this.exitTimeInterval) {
const context = getContext(this) as common.UIAbilityContext;
context.terminateSelf();
} else {
this.lastBackPressTime = currentTime;
promptAction.showToast({
message: "再按一次退出应用",
duration: 2000
});
}
return true;
}
// 其他代码...
}
上述代码通过记录两次返回键的间隔时间，如果小于设定的时间间隔（如2000毫秒），则终止应用程序。否则，显示一个Toast提示用户再次按返回键退出。
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