HarmonyOS 鸿蒙Next：json 转 class 有没有对应的方法

class address { street: string; city: string; state: string;

constructor(street:string,city:string,state:string) { this.street = street; this.city = city; this.state = state; } }

class jsonObj { address:address name: string; age: number; phoneNumbers: Array<string>;

constructor(name:string,age:number,address:address,phoneNumbers: Array<string>) { this.name = name; this.age = age; this.address = address; this.phoneNumbers = phoneNumbers; } }

@Entry @Component struct Index { @State message: string = ‘Hello World’

build() { Row() { Column() { Text(this.message) .fontSize(50) .fontWeight(FontWeight.Bold)

    Button(){
      Text("打印")
    }
    .width(150)
    .height(75)
    .onClick(()=>{
      let str = ["555-1234", "555-5678"]
      let add = new address("123 Main St","Anytown","CA");
      let json = new jsonObj("john",30,add,str)

      console.log(JSON.stringify(json.name));
      console.log(JSON.stringify(json.age));
      console.log(JSON.stringify(json.address));
      console.log(JSON.stringify(json.phoneNumbers));
    })
  }
  .width('100%')
}
.height('100%')

} }

系统规格问题：鸿蒙目前暂不支持，因为开启了严格的ARKTS语言检查，所以使用的data对象必须进行class类型的自定义，否则无法使用

不使用怎么获取网络数据给arkts使用，那怎么解析字符串为对象，怎么取字符串中的某些字段的值？

// 定义类型接口： interface userRespType{ nickname: string, avatar: string } interface dataType{ roomId: string, nativeUrl: string, status: string, userResp:Array<userRespType> } interface jsonObjectType{ reqId:string, code: number, msg: string, data:dataType }

let userResp:userRespType = { nickname: “一个很长的名字哈哈哈”, avatar: “https://aopsmsg.pingan.com.cn/group4/M01/2A/3C/HhDEeFqcsfiAY06aAAA0Fw-3GV0645.jpg#w=210;h=210” } let data:dataType = { roomId: “823688”, nativeUrl: “native://enterLiveRoom?RoomId=823688”, status: “1”, userResp: [ userResp ] } let jsonObj:jsonObjectType= { reqId: “2b2258ae54e3101a”, code: 0, msg: “success”, data:data } let json:string = JSON.stringify(jsonObj)

// 假设test为JSON.prase解析后的数据 let test:jsonObjectType = JSON.parse(json) console.info(test.msg) console.info(test.data.userResp[0].nickname)