Golang Go语言中 NATS-STREAMING 问题：先 publish 消息再启动 QueueSubscriber，相同队列仅一个 Subscriber 能消费消息？

PUBLISHER 代码：

func main() {
	nc,err := stan.Connect("test-cluster","idc",stan.NatsURL("nats://127.0.0.1:4222"))
	if err != nil{
		panic(err)
	}
	fmt.Println("connect succ")
	for i:=0;i<10;i++{
		fmt.Println("publishing:",i)
		err := nc.Publish("tp1",[]byte(strconv.Itoa(i)))
		if err != nil{
			panic(err)
		}
	}
	nc.Close()
}

QueueSubscriber 代码：

func main() {
	nc,err := stan.Connect("test-cluster","subscriber",stan.NatsURL("nats://localhost:4222"))
	if err != nil{
		panic(err)
	}
	defer nc.Close()
	subs := make([]stan.Subscription,3)
	for i:=0;i<3;i++{
		workername := "worker"+strconv.Itoa(i)
		fmt.Println(fmt.Sprintf("QueueSubscribe %s start",workername))
		sub,err := nc.QueueSubscribe("tp1","ch1", func(msg *stan.Msg) {
			fmt.Println(workername,"get msg:",string(msg.Data),"start doing something")
			time.Sleep(1*time.Second)
		},stan.DurableName("subscriber"),stan.AckWait(time.Hour*24))
		if err != nil{
			panic(err)
		}
		subs[i] = sub
	}
	c := make(chan os.Signal, 1)
	signal.Notify(c, os.Interrupt, os.Kill)
	select{
	case <- c:
		fmt.Println("Subscriber CLOSE")
		for i,_ := range subs{
			subs[i].Close()
		}
		nc.Close()
		fmt.Println("quit")
	}
}

Publisher 输出：

connect succ
publishing: 0
publishing: 1
publishing: 2
publishing: 3
publishing: 4
publishing: 5
publishing: 6
publishing: 7
publishing: 8
publishing: 9

QueueSubscriber 输出：

QueueSubscribe worker0 start
QueueSubscribe worker1 start
worker0 get msg: 0 start doing something
QueueSubscribe worker2 start
worker0 get msg: 1 start doing something
worker0 get msg: 2 start doing something
worker0 get msg: 3 start doing something
worker0 get msg: 4 start doing something
worker0 get msg: 5 start doing something
worker0 get msg: 6 start doing something
worker0 get msg: 7 start doing something
worker0 get msg: 8 start doing something
worker0 get msg: 9 start doing something

请问朋友们是否有遇到过一样的问题呢？谢谢大家