Python爬虫框架Scrapy使用问题求救

在爬取 http://real.hffd.gov.cn/index?servicetype= 这个网站时,获取不到每个小区的 url,请问如何获取?


Python爬虫框架Scrapy使用问题求救
5 回复

function reurl(a) {
a.href = “/item/” + recode(a.id)
}

function recode(a) {
var n = nscaler(a);
var c = SetObjNum(a.length);
var d = SetObjNum(a.length);
n = parseInt(n) + parseInt(d);
var b = $("#iptstamp").val();
b = nscaler(b.toString());
return c + “-” + n + “-” + d + “-” + b
}

function SetObjNum(n) {
var a = “”;
for (var i = 0; i < n; i++)
a += Math.floor(Math.random() * 10);
return a
}

function nscaler(a) {
var b = “”;
$.each(a, function(i, e) {
switch (e) {
case “0”:
b += “0”;
break;
case “1”:
b += “2”;
break;
case “2”:
b += “5”;
break;
case “3”:
b += “8”;
break;
case “4”:
b += “6”;
break;
case “5”:
b += “1”;
break;
case “6”:
b += “3”;
break;
case “7”:
b += “4”;
break;
case “8”:
b += “9”;
break;
case “9”:
b += “7”;
break
}
});
return b
}


我无法理解你的问题

受教!

这段 js 是从哪里得到的?

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