Python贪吃蛇游戏源码分享:来自Udemy课程的实现
python3 版的,使用了 pygame。 源码在这里: https://qiujunya.com/python3snake.html
Python贪吃蛇游戏源码分享:来自Udemy课程的实现
4 回复
搭车分享一个 JS 的贪吃蛇游戏。
预览地址: https://8bit-game-studio.github.io/RetroSnakerJS/RetroSnakerJS.html
源码地址: https://github.com/8bit-Game-Studio/RetroSnakerJS
import pygame
import random
import sys
# 初始化
pygame.init()
WIDTH, HEIGHT = 600, 600
GRID_SIZE = 20
GRID_WIDTH = WIDTH // GRID_SIZE
GRID_HEIGHT = HEIGHT // GRID_SIZE
FPS = 10
# 颜色
BLACK = (0, 0, 0)
WHITE = (255, 255, 255)
GREEN = (0, 255, 0)
RED = (255, 0, 0)
BLUE = (0, 120, 255)
# 方向
UP = (0, -1)
DOWN = (0, 1)
LEFT = (-1, 0)
RIGHT = (1, 0)
class Snake:
def __init__(self):
self.reset()
def reset(self):
self.length = 3
self.positions = [(GRID_WIDTH // 2, GRID_HEIGHT // 2)]
self.direction = RIGHT
self.score = 0
self.grow_pending = 2 # 初始长度3,还需增长2节
def get_head_position(self):
return self.positions[0]
def turn(self, point):
if self.length > 1 and (point[0] * -1, point[1] * -1) == self.direction:
return # 不能直接反向
self.direction = point
def move(self):
head = self.get_head_position()
x, y = self.direction
new_x = (head[0] + x) % GRID_WIDTH
new_y = (head[1] + y) % GRID_HEIGHT
new_position = (new_x, new_y)
# 检查是否撞到自己
if new_position in self.positions[1:]:
self.reset()
return False
self.positions.insert(0, new_position)
if self.grow_pending > 0:
self.grow_pending -= 1
else:
self.positions.pop()
return True
def grow(self):
self.grow_pending += 1
self.length += 1
self.score += 10
def draw(self, surface):
for i, p in enumerate(self.positions):
color = GREEN if i == 0 else BLUE # 头部绿色,身体蓝色
rect = pygame.Rect(p[0] * GRID_SIZE, p[1] * GRID_SIZE, GRID_SIZE, GRID_SIZE)
pygame.draw.rect(surface, color, rect)
pygame.draw.rect(surface, BLACK, rect, 1)
class Food:
def __init__(self):
self.position = (0, 0)
self.randomize_position()
def randomize_position(self):
self.position = (random.randint(0, GRID_WIDTH - 1), random.randint(0, GRID_HEIGHT - 1))
def draw(self, surface):
rect = pygame.Rect(self.position[0] * GRID_SIZE, self.position[1] * GRID_SIZE, GRID_SIZE, GRID_SIZE)
pygame.draw.rect(surface, RED, rect)
pygame.draw.rect(surface, BLACK, rect, 1)
def draw_grid(surface):
for y in range(0, HEIGHT, GRID_SIZE):
for x in range(0, WIDTH, GRID_SIZE):
rect = pygame.Rect(x, y, GRID_SIZE, GRID_SIZE)
pygame.draw.rect(surface, BLACK, rect, 1)
def main():
screen = pygame.display.set_mode((WIDTH, HEIGHT))
pygame.display.set_caption("Python贪吃蛇")
clock = pygame.time.Clock()
snake = Snake()
food = Food()
font = pygame.font.SysFont('arial', 25)
while True:
for event in pygame.event.get():
if event.type == pygame.QUIT:
pygame.quit()
sys.exit()
elif event.type == pygame.KEYDOWN:
if event.key == pygame.K_UP:
snake.turn(UP)
elif event.key == pygame.K_DOWN:
snake.turn(DOWN)
elif event.key == pygame.K_LEFT:
snake.turn(LEFT)
elif event.key == pygame.K_RIGHT:
snake.turn(RIGHT)
if not snake.move():
continue # 如果重置了,继续下一帧
# 检查是否吃到食物
if snake.get_head_position() == food.position:
snake.grow()
food.randomize_position()
# 确保食物不出现在蛇身上
while food.position in snake.positions:
food.randomize_position()
# 绘制
screen.fill(WHITE)
draw_grid(screen)
snake.draw(screen)
food.draw(screen)
# 显示分数
score_text = font.render(f'Score: {snake.score}', True, BLACK)
screen.blit(score_text, (5, 5))
pygame.display.update()
clock.tick(FPS)
if __name__ == "__main__":
main()
这个实现包含了贪吃蛇的核心逻辑:蛇的移动、转向限制、食物生成和碰撞检测。代码结构清晰,直接运行即可玩。
一不小心跑到墙里就出不来了,好贪吃。
可以原路返回…😂

