Python中遇到程序执行顺序的问题，大神们帮忙看下
import logging
from time import time as t
import time
logger = logging.getLogger()
logger.setLevel(logging.DEBUG)
is_debug = True
def count_time(is_debug):
def handle_func(func):
def handle_args(*args, **kwargs):
if is_debug:
begin = t()
func(*args, **kwargs)
print ‘args2’,‘kwargs2’,args,kwargs
logging.debug( “[” + func.name + "] -> " + str(t() - begin) )
else:
func(*args, **kwargs)
print ‘handle_args’, handle_args
print type(handle_args)
return handle_args
return handle_func
def pr():
for i in range(1,1000):
i = i * 2
time.sleep(0.01)
print “hello world”,t()
def test():
pr()
print ‘test’
@count_time(is_debug)
def test2():
pr()
print ‘test2’
@count_time(False)
def test3():
pr()
print ‘test3’
if name == “main”:
test()
test2()
test3()
结果
C:\Python27\python.exe D:/python/pyworkspcae/testdeco/timedeco.py
hello world 1500518211.89
test
hello world 1500518221.92
DEBUG:root:[test2] -> 10.0350000858
test2
args2 kwargs2 () {}
hello world 1500518232.03
test3
handle_args <function handle_args at 0x00000000029C6518>
<type ‘function’>
Process finished with exit code 0
DEBUG 输出这条信息顺序看不懂
Python中遇到程序执行顺序的问题，大神们帮忙看下
抱歉，没注意排版就发了，补一个 gist https://gist.github.com/iamsunxin/b1de234354fafeb91f5fb890e433bd0a
这是典型装饰器啊.
简单理解,就是
(is_debug)
def test2():
pr()
print 'test2’
单实际执行的是,
def count_time(is_debug):
def handle_func(test2):
def handle_args(*args, **kwargs):
if is_debug:
begin = t()
test2(*args, **kwargs)
print (‘args2’, ‘kwargs2’, args, kwargs)
logging.debug("[" + func.name + "] -> " + str(t() - begin))
else:
func(*args, **kwargs)
print (‘handle_args’, handle_args)
print (type(handle_args))
return handle_args
return handle_func
logging.debug 按代码是输出到了 stderr，print 输出到 stdout
而一般 stdout 是带缓冲的，stderr 不带缓冲立即输出
LZ 可以试试把 stdout 和 stderr 分开输出
python.exe timedeco.py >stdout.txt 2>stderr.txt
