Python 文本格式处理问题
文本如下
Storage 1:
total storage = 204699 MB
free storage = 195091 MB
Storage 2:
total storage = 204699 MB
free storage = 200661 MB
如何实现最终结果为
Storage_1_total_storage = 204699 MB
Storage_1_free_storage = 195091 MB
Storage_2_total_storage = 204699 MB
Storage_2_free_storage = 200661 MB
Python 文本格式处理问题
如果 Storage total storage 这些都是固定的话，用正则可以这么写：Storage (\d+):\ntotal storage = (.+)\nfree storage = (.+)
如果不固定的话还是别用正则了，逐行遍历可能没那么麻烦。
for line in file:
if line[-1:] == ‘:’:
prefix = line[:-1].replace(’ ‘, ‘’)
else:
print (prefix+’’+line.replace(’ ', ‘_’, 1))
for line in text :
if line.startswith(‘Storage’) :
s = line.strip().replace( ’ ', ‘’ )［:-1 ］
else :
k,v = line.split(’=’)
k = k.strip().replace( ’ ', '’ )
line = ‘%s_%s = %s’ % ( s, k, v )
out.write(line)
差不多就这样
python3<br>for line in open("new.txt", "r"):<br> line = line.rstrip()<br> if line.startswith("Storage "):<br> storage = line.rstrip(':')<br> else:<br> key, val = map(lambda x:x.strip(), line.split('='))<br> new_key = f"{storage}_{key}".replace(' ', '_')<br> print(f"{new_key} = {val}")<br>
